- $\frac{u\epsilon}{\nu}\sim 1$.
Assuming the smallest scale carries a substantial part of the total dissipation gives
- $\nu(\frac{u}{\epsilon})^2\sim 1$.
Combination gives
- $u\sim \nu^{\frac{1}{4}}$
- $\epsilon\sim\nu^{\frac{3}{4}}$
suggesting that the turbulent solution is Lipschitz continuous with exponent $\frac{1}{3}$.
My question to Tao posed as a post comment is if according to the Clay problem formulation, such a $Lip^\frac{1}{3}$ turbulent solution with smallest scale $\nu^\frac{3}{4}$ is to be viewed as a smooth solution for any small $\nu >0$?
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