Our Milky Way Galaxy as a weakly compressible gas modeled by the Euler equations expressing conservation of mass, momentum and energy, combined with constitutive laws connecting pressure and gravitational forces to mass density.
After the excursion on Newton vs Einstein in recent posts, we are back to a cosmological model in the form of Euler's equations for a compressible gas subject to Newtonian gravitation: Find $(\rho ,m, e ,\phi ,p)$ depending on a Euclidean space coordinate $x$ and time $t$ , such that for all $(x,t)$:
- $\dot\rho + \nabla\cdot (\rho u ) =0$ (or $\frac{D\rho}{Dt} = -\rho\nabla\cdot u$)
- $\dot m +\nabla\cdot (mu) +\nabla p + \rho\nabla\phi =0$
- $\dot e +\nabla\cdot (eu) +p\nabla\cdot u +\rho\nabla\cdot m=0$,
- $\frac{D\rho}{Dt}=\dot\rho +u\cdot\nabla\rho$
These equations express conservation of mass $\rho$, conservation of momentum $m$ with $\nabla p$ pressure force and $-\nabla\phi$ gravitational force, and conservation of internal energy $e$. These laws of conservation are complemented with constitutive laws connection $p$ and $\phi$ to density of the following form:
A1: Weakly compressible gas ($\delta$ small positive constant):
- $\Delta p =\frac{\nabla\cdot u}{\delta}= - \frac{1}{\delta\rho}\frac{D\rho}{Dt}$
A2: Compressible perfect gas ($0 < \gamma < 1 $):
- $p=\gamma \rho T$.
- $\Delta\phi =\rho$ with $\phi =0$ at infinity.
- Similarity of $\nabla p$ and $\nabla\phi$ in momentum equation.
- Similarity between A1 and B connecting $\Delta p$ to $-\frac{D\rho}{Dt}$ (or $-\rho$) and $\Delta\phi$ to $\rho$.
- $p \ge 0$ and $\phi \le 0$.
The relation $\Delta\phi =\rho$ is explored in Newtonian Matter and Antimatter with $\Delta\phi > 0$ identifying matter and $\Delta\phi < 0$ antimatter. Mind-boggling!
It may be that the above Newtonian model is just as good (or even better) than Einstein's equations as cosmological model, because it is understandable and may contain relevant large scale physics without the mysteries of "curved space-time fabric" of general relativity.
Second Law of Thermodynamics
Viscosity solutions of the Euler equations satisfy the following 2nd law:
- $\dot K = W_p + W_\phi - D$
- $\dot E = - (W_p + W_\phi ) + D$,
- $K=\int\frac{\vert m\vert^2}{2\rho}\, dx$ is total kinetic energy
- $E=\int e\, dx$ is total internal energy
- $W_p=\int p\nabla\cdot u\, dx$ is total work performed by pressure
- $W_\phi =\int \phi\nabla\cdot m\, dx$ is total work performed by gravitation
- $D>0$ is turbulent dissipation.
- $W_\phi =- \int \phi\dot\rho\, dx =-\int\phi\Delta\dot \phi\, dx =\frac{d}{2dt}\int\vert\nabla\phi\vert^2\, dx$.
Choice of coordinate system
The Euclidean coordinate system could be fixed to distant fixed stars with the origin at the projected center of the universe. A rotation of this system would show up as extra centrifugal forces, which could explain the apparent accelerated expansion of the universe.
Uni-directional transfer of energy - Alternative pressure laws
Note that A1 implies that $W_p= - \int\delta\int\vert\nabla p\vert^2\, dx < 0$ showing uni-directional transfer of energy from kinetic energy to internal energy. Transfer in the other direction can appear with the stronger effect of compressibility in A2. Of course, combinations of A1 and A2 are thinkable, as well as a pressure analog of B in the form A3: $-\Delta p \sim e$ with $e=\rho T$ and $T$ temperature.
Recall that $W_\phi = \frac{d}{2dt}\int\vert\nabla\phi\vert^2\, dx$, thus with a positive contribution to kinetic energy $K(t)$ over time.
Basic dynamics
The basic dynamics of the above Euler model can be described as local gravitational collapse with gravitational energy being transformed first into kinetic energy and then into heat energy, followed by pressure build up setting a limit to concentration of matter, leading to cosmic web of matter separated by voids:
Visible matter would correspond to $\Delta\phi$ being singular (points, lines, surfaces), while dark matter would correspond to $\Delta\phi$ being smoothly distributed (and positive).
PS Note that the momentum equation can be formulated:
- $\rho\dot u +\rho u\cdot \nabla u + \nabla p + \rho\nabla\phi =0$, that is
- $\dot u +\rho u\cdot \nabla u + \nabla\phi = F$ or $\frac{Du}{Dt} + \nabla\phi = F$,



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