tag:blogger.com,1999:blog-1500584444083499721.post6061832444838858902..comments2024-02-29T11:22:30.853+01:00Comments on CJ on Mathematics and Science: Making the Fiction of DLR RealClaes Johnsonhttp://www.blogger.com/profile/07411413338950388898noreply@blogger.comBlogger25125tag:blogger.com,1999:blog-1500584444083499721.post-55640130779427283372013-01-22T21:55:57.936+01:002013-01-22T21:55:57.936+01:00Maybe you should take a closer look at solid state...Maybe you should take a closer look at solid state physics...Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-27549869513826620922013-01-22T21:47:12.854+01:002013-01-22T21:47:12.854+01:00There are many books on Maxwell's equations an...There are many books on Maxwell's equations and electromagnetic waves with lots of information. Less is known about interaction between matter and EM-waves and blackbody radiation. In fact classical continuum physics collapsed on this problem at the end of 19th century, because of the ultraviolet catastrophe. I seek to resurrect classical continuum physics using a notion of finite precision computation, because the alternative of quantum mechanics cannot handle macroscopic pbenomena such as blackbody radiation.Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-34887892201353487782013-01-22T21:08:14.472+01:002013-01-22T21:08:14.472+01:00And you know nothing about the energy and momentum...And you know nothing about the energy and momentum in electromagnetic waves in connection to your model then?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-6254136210329011792013-01-22T19:11:15.595+01:002013-01-22T19:11:15.595+01:00I am a mathematician and I analyze mathematical mo...I am a mathematician and I analyze mathematical models of physical phenomena and want to keep the discussion connected to the model in order to know what to say. If you want to speak about physics without precise mathematical models, I suggest you turn to a physicist.Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-71957286873178125642013-01-22T18:29:10.193+01:002013-01-22T18:29:10.193+01:00Please sir, you asked me to specify my original qu...Please sir, you asked me to specify my original question. <br /><br /><a href="http://claesjohnson.blogspot.com/2013/01/making-fiction-of-dlr-real.html?showComment=1358804382338#c518875786448936519" rel="nofollow"> How does the energy of an electromagnetic wave fit into this? </a><br /><br />And then started this silly game of "20 questions", what do you mean with this, what do you mean with that. Why are you playing silly games?<br /><br />You seem extremely reluctant in explaining the details of your model and your train of thoughts. You say you model physics, but you do not want to discuss the physics.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-32098000668529780872013-01-22T18:17:18.476+01:002013-01-22T18:17:18.476+01:00It does not make sense to me: what do mean by &qu...It does not make sense to me: what do mean by "transports" and "deposits" and "recieving charge". I am pretty tired of this conversation. Why don't you ask a physicist instead? Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-79608354105756732162013-01-22T18:09:03.052+01:002013-01-22T18:09:03.052+01:00That it transports energy and momentum from the so...That it transports energy and momentum from the source (that's the two Maxwell equations above) and deposit it according to the Lorentz force law, dp/dt = qF, wich gives the change in the energy and momentum of the receiving charge.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-32433427922011467392013-01-22T16:00:47.350+01:002013-01-22T16:00:47.350+01:00What does "carry" mean?What does "carry" mean?Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-43187727746075257672013-01-22T12:54:31.398+01:002013-01-22T12:54:31.398+01:00Given the 4-vector p. Energy is the null component...Given the 4-vector p. Energy is the null component of p, momentum is the space-like three vector of p.<br /><br />dp/dt = qF,<br /><br />q is the charge.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-73463715517866094992013-01-22T12:49:11.140+01:002013-01-22T12:49:11.140+01:00What does "carry" mean, what is "en...What does "carry" mean, what is "energy" and what is "momentum" in terms of F?Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-67603890817755585902013-01-22T12:37:42.353+01:002013-01-22T12:37:42.353+01:00You have an electromagnetic field F that satisfies...You have an electromagnetic field F that satisfies Maxwell's equations (d*F = 4pi*J, div F = 4pi J), J is the 4-current.<br /><br />Does F carry energy and momentum?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-86615436873378446662013-01-22T12:27:11.996+01:002013-01-22T12:27:11.996+01:00If you formulate your question as a question about...If you formulate your question as a question about solutions of Maxwell's equations it may be answered. So what is your question then?Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-5812158464798551402013-01-22T11:35:43.146+01:002013-01-22T11:35:43.146+01:00Does that mean that you are not sure if electromag...Does that mean that you are not sure if electromagnetic waves carry energy and momentum?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-249574090037779752013-01-22T11:30:35.797+01:002013-01-22T11:30:35.797+01:00Electromagnetic waves are solutions to Maxwell'...Electromagnetic waves are solutions to Maxwell's wave equation. That is all there is to say. The true nature of electromagnetism is unknown.Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-76874629800341334312013-01-22T10:41:22.061+01:002013-01-22T10:41:22.061+01:00As I said, your model is very obscure.
How do you...As I said, your model is very obscure.<br /><br />How do you define a blackbody for instance?<br /><br />Further, the electromagnetic theory is not about photons, it is about waves. According to you, does these waves carry momentum and energy?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-45582174257641620042013-01-22T10:29:53.032+01:002013-01-22T10:29:53.032+01:00You have to look at the model I study in the black...You have to look at the model I study in the blackbody book, with radiative heat transfer as a resonance phenomenon with high-frequency cut-off, and not as a particle phenomenon with gigantic infrared photons crawling in and out. Why not ask physicist, to see if that helps. They are paid to have answers.Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-11311305236265240892013-01-22T08:26:05.209+01:002013-01-22T08:26:05.209+01:00Well, I'm a bit acquainted with EM-theory, I h...Well, I'm a bit acquainted with EM-theory, I have read Jackson for instance. That's not important, I'm curious of your treatment.<br /><br />Does the waves leaving a body carry momentum and energy?<br /><br />It is very obscure, and you are being vague here to.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-24725521430310587872013-01-22T08:09:47.360+01:002013-01-22T08:09:47.360+01:00I suggest a model for matter-electromagnetic wave ...I suggest a model for matter-electromagnetic wave interaction in my blackbody which carries an answer.<br />Why not ask a physicist about matter-EM wave interaction?Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-5188757864489365192013-01-21T22:39:42.338+01:002013-01-21T22:39:42.338+01:00How does the energy of an electromagnetic wave fit...How does the energy of an electromagnetic wave fit into this?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-14788663980670265692013-01-21T16:15:56.046+01:002013-01-21T16:15:56.046+01:00Heat energy is in thermodynamics the total energy ...Heat energy is in thermodynamics the total energy (which is conserved) minus kinetic and potential and chemical energy. It is also called internal energy, because it has a limited capability of being transformed into e.g. kinetic energy.Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-54302794405119755212013-01-21T15:32:22.103+01:002013-01-21T15:32:22.103+01:00No it is not clear.
First, how do you define heat...No it is not clear.<br /><br />First, how do you define heat energy?<br /><br />And secondly, is there any other kinds of energy than heat involved?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-13966801422098220982013-01-21T15:25:29.880+01:002013-01-21T15:25:29.880+01:00One way heat flux is transfer of heat energy from ...One way heat flux is transfer of heat energy from warm to cold body, like a one-way street with all cars moving in one direction. Two-way heat flux is gross transfer of heat energy from warm to cold and from cold to warm (DLR) at a the same time, like a two-way street with cars moving in both directions. Is this clear?Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-44095041137927137882013-01-21T13:28:42.942+01:002013-01-21T13:28:42.942+01:00Could you please make a precise definition of exac...Could you please make a precise definition of exactly what you mean by one-way heat flux and two-way heat flux.<br /><br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-60369931548273342152013-01-20T14:07:43.219+01:002013-01-20T14:07:43.219+01:00There is no two-way flux of heat back and forth.
D...There is no two-way flux of heat back and forth.<br />DLR is fiction.Claes Johnsonhttps://www.blogger.com/profile/07411413338950388898noreply@blogger.comtag:blogger.com,1999:blog-1500584444083499721.post-87239820030761968812013-01-20T12:58:49.378+01:002013-01-20T12:58:49.378+01:00The LP PIRG 01 manual
http://www.deltaohm.com/ver2...The LP PIRG 01 manual<br />http://www.deltaohm.com/ver2012/download/LP_Pirg_01_M_uk.pdf<br />as says about the device working principle:<br /><br /><i>Radiant energy is absorbed/radiated from the surface of the blackened thermopile, <b>creating a temperature difference</b> between the centre of the thermopile (hot junction) and the body of pyrgeometer (cold junction). <b>The temperature difference</b> between hot and cold junction <b>is converted into Potential Difference thanks to the Seebeck effect.</b></i><br /><br />Then the device works because of the <b>ΔT</b> produced by the heat power absorbed/radiated.<br /><br /><i><b>If the pyrgeometer temperature is higher than the radiant temperature of the portion of sky framed by the pyrgeometer, the thermopile will irradiate energy and the output signal will be negative (typical situation of clear sky) vice versa if the pyrgeometer temperature is lower than that portion of sky framed, the signal will be positive (typical situation of cloudy sky).</b></i><br /><br />In other words the heat power transfer is one way. All is right, there is no fraud. The fraud is made by those who confuse the device upward radiation with the sky downward radiation.<br /><br />Michael<br />Anonymousnoreply@blogger.com